Skip to main content
Iota

Return to Question

Notice added Legacy IOTA protocol by mihi♦
edited tags
Link
mihi ♦
mihi ♦
  • 7.3k
  • 2
  • 16
  • 34
Bumped by Community user
Bumped by Community user
added 5 characters in body
Source Link
Avelino
Avelino
  • 435
  • 3
  • 8

I had a hard time answering this question because I do not know how much security levels improve security in quantitative terms.

Is this right?

e.g. (Hashspace increment)

  • 81 trits => 27^81 ^1 (low security)
  • 162 trits => 27^81 ^2 (medium security)
  • 243 trits => 27^81 ^3 (high security) [Citation needed]

e.g. (Attempts increment)

  • 81 trits => 1* 27^81 attempts (low security)
  • 162 trits => 2* 27^81 attempts (medium security) //Two times more attempts//Two times more attempts?
  • 243 trits => 3* 27^81 attempts (high security) [Citation needed]

I had a hard time answering this question because I do not know how much security levels improve security in quantitative terms.

Is this right?

e.g. (Hashspace increment)

  • 81 trits => 27^81 ^1 (low security)
  • 162 trits => 27^81 ^2 (medium security)
  • 243 trits => 27^81 ^3 (high security) [Citation needed]

e.g. (Attempts increment)

  • 81 trits => 1* 27^81 attempts (low security)
  • 162 trits => 2* 27^81 attempts (medium security) //Two times more attempts
  • 243 trits => 3* 27^81 attempts (high security) [Citation needed]

I had a hard time answering this question because I do not know how much security levels improve security in quantitative terms.

Is this right?

e.g. (Hashspace increment)

  • 81 trits => 27^81 ^1 (low security)
  • 162 trits => 27^81 ^2 (medium security)
  • 243 trits => 27^81 ^3 (high security) [Citation needed]

e.g. (Attempts increment)

  • 81 trits => 1* 27^81 attempts (low security)
  • 162 trits => 2* 27^81 attempts (medium security) //Two times more attempts?
  • 243 trits => 3* 27^81 attempts (high security) [Citation needed]
Source Link
Avelino
Avelino
  • 435
  • 3
  • 8

How much of my security is improved using other levels of security when generating the seed?

I had a hard time answering this question because I do not know how much security levels improve security in quantitative terms.

Is this right?

e.g. (Hashspace increment)

  • 81 trits => 27^81 ^1 (low security)
  • 162 trits => 27^81 ^2 (medium security)
  • 243 trits => 27^81 ^3 (high security) [Citation needed]

e.g. (Attempts increment)

  • 81 trits => 1* 27^81 attempts (low security)
  • 162 trits => 2* 27^81 attempts (medium security) //Two times more attempts
  • 243 trits => 3* 27^81 attempts (high security) [Citation needed]